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Entrance exams: geometry

Perimeters, areas, Pythagoras and a sketch as a rescue.

Geometry starts with a sketch

The second pillar of entrance exams: geometry. Perimeters, areas, Pythagoras’ theorem, solids, angles. It sounds like a pile of formulae — but really it is mainly one skill: make a sketch.

A geometry question without a sketch is like a map read with your eyes shut. With a sketch the question mostly solves itself: you draw, you label known sizes, and suddenly you see what is missing and which way to go.

The formulae entrance exams really want are surprisingly few: perimeter and area of a square, a rectangle, a triangle and a circle, Pythagoras’ theorem, the sum of angles in a triangle (180°), the volume of a cuboid and a cylinder. That is the core. You have them in your head from earlier levels — today we dust them off in test mode.

And again, calm: geometry questions tend to be generous with marks and the method is marked. Even if the last step does not come out, a correct sketch and a started calculation carry marks. Pencil in hand, let’s draw.

Adam in a practice test skipped a question about a ladder against a wall — “too much text, I don’t get it”. Sofie shows it her way: she draws a wall, the ground, a slanted ladder. “See? A right-angled triangle. The ladder is the hypotenuse 5 metres, from the wall 3 metres — you look for the height.” Adam looks: “Ah, that is ordinary Pythagoras! 25 minus 9 is 16, height 4 metres.” Sofie shrugs: “The question was not hard. It was just dressed in text. A sketch undressed it.”

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A sketch does not have to be pretty or exact. It must have all the sizes from the question labelled and a question mark by what you look for. You draw a helper, not art.

A test method for a geometry question

Step 1: Sketch and labels. Read the question, draw the situation, by each line write a size from the question. By the sought quantity a question mark.

Step 2: Tên the shape. “That is a right-angled triangle.” “That is a rectangle with a circular hole.” Once you name the shape, the formula reports for duty on its own.

Step 3: Pick a formula according to the question. Perimeter = the path around (metres, cm). Area = the space inside (m², cm²). Volume = the space inside a solid (m³, cm³). The unit in the question gives away the formula.

Step 4: Substitute and calculate line by line. Pythagoras: c² = a² + b² (the hypotenuse last — it is the longest). Circle: circumference 2 · π · r, area π · r², with π ≈ 3.14. Watch diameter versus radius!

Step 5: Answer with a unit and check with sense. Hypotenuse longer than the legs? Area positive? The height of a house did not come out 250 m?

The most common test traps: a given diameter instead of a radius (divide by two), units in different systems (metres and centimetres in one question — unify), perimeter mixed up with area, and a “forgotten half” with a triangle (area = a · v / 2, not a · v).

Example 1: Pythagoras in text

Question (a test type): A ladder 5 m long leans against a wall. Its foot stands 3 m from the wall. To what height does the ladder reach?

Method: Sketch: wall vertical, ground horizontal, ladder slanted. A right angle between the wall and the ground.

Ladder = hypotenuse c = 5. Distance from the wall = leg a = 3. I look for leg b.

Pythagoras: b² = c² − a² = 25 − 9 = 16. So b = 4.

Sense check: 4 m is less than the length of the ladder 5 m — a leg shorter than the hypotenuse. It matches.

Answer: The ladder reaches a height of 4 m.

Example 2: the area of a composite shape

Question: A garden has the shape of a rectangle 12 × 8 m. In the middle is a circular pool with diameter 4 m. How many m² is left for lawn? (π ≈ 3.14)

Method: Sketch: a rectangle, a circle in it.

Rectangle: 12 · 8 = 96 m².

Circle: diameter 4 → radius 2. Area = 3.14 · 2² = 3.14 · 4 = 12.56 m².

Lawn = rectangle minus circle: 96 − 12.56 = 83.44 m².

Answer: 83.44 m² is left for lawn. The trap of the question was in the diameter — who put in 4 as the radius got a circle four times bigger.

Example 3: angles in a triangle

Question: In a triangle one angle is 90° and the second is four times bigger than the third. Find the other two angles.

Method: The sum of angles in a triangle is 180°. For the other two, 180 − 90 = 90° is left.

I label the third angle x, the second is 4x. Equation: x + 4x = 90, so 5x = 90, so x = 18°.

Second angle: 4 · 18 = 72°.

Check: 90 + 72 + 18 = 180°. It matches.

Answer: The other angles are 72° and 18°. Geometry and an equation in one question — a common mix in entrance exams.

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Diameter is not radius. The most profitable trap of test questions with a circle and a cylinder: the question gives a diameter and the formula wants a radius. Before you substitute, underline the word “diameter” or “radius” in the question and by a diameter at once write r = diameter/2. One underline, one saved mark.

Practice: now you do it 🎲

Now try it for real. You will see all the questions at once, like on paper. Bắt đầu with ten. When it goes well, add more.

Pythagoras’ theorem — the most common geometry guest of entrance exams. Write a whole number.

Practise the questions

On paper

A test set. For every question a required sketch with labelled sizes — we train a habit, not speed.

  1. A rectangular garden 15 × 9 m: calculate the perimeter (for a fence) and the area (for grass). Watch the units: m against m².

  2. A right-angled triangle with legs 6 cm and 8 cm: calculate the hypotenuse and the area. (The area of a right-angled triangle = leg times leg divided by two.)

  3. A circular flower bed with diameter 6 m: circumference and area, π ≈ 3.14. Radius first!

  4. A cuboid aquarium 40 × 25 × 30 cm: how many litres of water does it hold? (1 litre = 1000 cm³.)

Now you 💪

  1. Every question starts with a sketch with sizes and a question mark.
  2. From a diameter you make a radius before you reach for a formula.
  3. You answer with a unit and check the result with sense.

Done when: You have four solved test questions, each with a sketch, the right unit and a sense check.

What to take from this lesson